alphabet version 3
May 19, 2007 | 6:32 pmThird answer to my alphabet question:
#include <stdio.h> void main () { char Array[26] = { 'a', 'b', ... 'z'}; int i; for (i = 0; i <= 26; i++) { printf(%c\\n, *Array[i]); } exit; }
Download this code: alphabet_3.c (140 hits)
There is no typo in the transcript. What do you think? Is my question ‘too hard’? Is it not ‘appropriate’ for a ‘C’ developer position?



