alphabet version 2

Second answer… again, there is no typo, this is the pure transcript of the candidate’s answer.

main(argc, argv[])
{
    int i = 0;
    char a[26] = { 'a', 'b', 'c', ...'z'}
 
    for (i = 0; i <=26; i++)
    {
        printf("%d/n", a[i]%);
    }
    return;
}
 

Download this code: alphabet_2.c

With this question, I’m realizing that array usage in C, is clearly not clear for everyone.